=(a^2+a+1)(a-1)

Solution for =(a^2+a+1)(a-1) equation:

Simplifying
0 = (a2 + a + 1)(a + -1)

Reorder the terms:
0 = (1 + a + a2)(a + -1)

Reorder the terms:
0 = (1 + a + a2)(-1 + a)

Multiply (1 + a + a2) * (-1 + a)
0 = (1(-1 + a) + a(-1 + a) + a2(-1 + a))
0 = ((-1 * 1 + a * 1) + a(-1 + a) + a2(-1 + a))
0 = ((-1 + 1a) + a(-1 + a) + a2(-1 + a))
0 = (-1 + 1a + (-1 * a + a * a) + a2(-1 + a))
0 = (-1 + 1a + (-1a + a2) + a2(-1 + a))
0 = (-1 + 1a + -1a + a2 + (-1 * a2 + a * a2))
0 = (-1 + 1a + -1a + a2 + (-1a2 + a3))

Combine like terms: 1a + -1a = 0
0 = (-1 + 0 + a2 + -1a2 + a3)
0 = (-1 + a2 + -1a2 + a3)

Combine like terms: a2 + -1a2 = 0
0 = (-1 + 0 + a3)
0 = (-1 + a3)

Solving
0 = -1 + a3

Solving for variable 'a'.

Move all terms containing a to the left, all other terms to the right.

Add '-1a3' to each side of the equation.
0 + -1a3 = -1 + a3 + -1a3
Remove the zero:
-1a3 = -1 + a3 + -1a3

Combine like terms: a3 + -1a3 = 0
-1a3 = -1 + 0
-1a3 = -1

Divide each side by '-1'.
a3 = 1

Simplifying
a3 = 1

Reorder the terms:
-1 + a3 = 1 + -1

Combine like terms: 1 + -1 = 0
-1 + a3 = 0

The solution to this equation could not be determined.